The correct option is A C_6H_5COOMgI C_6H_5 COOH + CH_3MgI → C_6H_5COO^ Mg^+I + CH_4 Since grignard reagent is strong base so it abstracts proton fro ...

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Standard XII

Chemistry

Acidity of Carboxylic Acids

C6H5COOH+CH3M...

Question

$C_{6} H_{5} C O O H + {C H}_{3} M g I \to$ ?

C_{6} H_{5} C O O M g I

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{C H}_{4}

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Both a and b

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none

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Solution

The correct option is A $C_{6} H_{5} C O O M g I$
$C_{6} H_{5} - C O O H + C H_{3} M g I \to C_{6} H_{5} C O O^{-} M g^{+} I + C H_{4}$
Since grignard reagent is strong base so it abstracts proton from acid to give salt( $C H_{3}^{-} + H^{+}$ ) and methane( $C H_{4}$ )

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Similar questions

Q. Identify the final product (

B

) of the reaction

C_{6} H_{5} C O O H + N a H * C O_{3} ⟶ g a s (A) 1. {C H}_{3} M g B r - ------ \to 2. H_{3} O^{+} (B) (* C = C^{14})

Q. Identify the major products in the following reaction.

C_{6} H_{5} C O O H + M e M g I ⟶ ? + ?

Q. Consider the two solutions:
I. 0.5 M

N a C l

aqueous solution at

25^{o} C

;

N a C l

is completely ionized.
II. 2.0 M

C_{6} H_{5} C O O H

in benzene at

25^{o} C; C_{6} H_{5} C O O H

dimerizes to the full extent.
Which of the following statements(s) is/are correct?

Q. Find the value of

^{6} C_{0} .^{12} C_{6} -^{6} C_{1} .^{11} C_{6} +^{6} C_{2} .^{10} C_{6} +^{6} C_{2} .^{10} C_{6} -^{6} C_{3} .^{9} C_{6} +^{6} C_{4} .^{8} C_{6} -^{6} C_{5} .^{7} C_{6} +^{6} C_{6} .^{6} C_{6}

Q. The increasing order of stability of the following free radicals is .

1. {{(C H}_{3})}_{2} ˙ C H < {{(C H}_{3})}_{3} ˙ C < (C_{6} {H_{5})}_{2} ˙ C H < (C_{6} {H_{5})}_{3} ˙ C 2. (C_{6} {H_{5})}_{3} ˙ C < (C_{6} {H_{5})}_{2} ˙ C H < {{(C H}_{3})}_{3} ˙ C < {{(C H}_{3})}_{2} ˙ C H 3. (C_{6} {H_{5})}_{2} ˙ C H < (C_{6} {H_{5})}_{3} ˙ C < {{(C H}_{3})}_{3} ˙ C < {{(C H}_{3})}_{2} ˙ C H 4. {{(C H}_{3})}_{2} ˙ C H < {{(C H}_{3})}_{3} ˙ C < (C_{6} {H_{5})}_{3} ˙ C < (C_{6} {H_{5})}_{2} ˙ C H

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C6H5COOH+CH3MgI→?

The correct option is A C6H5COOMgIC6H5−COOH+CH3MgI→C6H5COO−Mg+I+CH4Since grignard reagent is strong base so it abstracts proton from acid to give salt(CH−3+H+) and methane(CH4)

$C_{6} H_{5} C O O H + {C H}_{3} M g I \to$ ?

The correct option is A $C_{6} H_{5} C O O M g I$
$C_{6} H_{5} - C O O H + C H_{3} M g I \to C_{6} H_{5} C O O^{-} M g^{+} I + C H_{4}$
Since grignard reagent is strong base so it abstracts proton from acid to give salt( $C H_{3}^{-} + H^{+}$ ) and methane( $C H_{4}$ )