Question

$C_6{H}_{5}OH+CHC{l}_3+NaOH\to C_6{H}_4\left(CHO\right)OH$
In the above reaction, the electrophile involved is:

• A. dichloromethyl cation $\left(\stackrel{⨁}{C}HC{l}_2\right)$
• B. dichlorocarbene $(:CC{l}_2)$
• C. trichloromethyl anion $\left({}^{-}CC{l}_3\right)$
• D. formyl cation $\left(\stackrel{⨁}{C}HO\right)$

Answer 1

The correct option is B dichlorocarbene $(:CC{l}_2)$

$NaOH+CC{l}_3^{-}\to :CC{l}_2+NaC{l}^{-}+H_{2}O$

Here , electrophile is dichlorocarbene $\left(3\right)$.

Hence, the correct option is B.