$C_{6} H_{5} - C O O A g + B r_{2} + C C l_{4} + r e f l u x \to$

C_{6} H_{5} - B r + C O_{2} + A g B r

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C_{6} H_{5} - B r + C O + A g B r

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C_{6} H_{5} - B r + 2 C O_{2} + A g B r

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none of these

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Solution

The correct option is A $C_{6} H_{5} - B r + C O_{2} + A g B r$
$C_{6} H_{5} - C O O H g + B r_{2} + C C l_{4} + r e f l u x \to C_{6} H_{5} - B r + C O_{2} + A g B r$
Above Given is hunsdiecker reaction
$R - C O O H + A g B r_{2} - ------ \to C C l_{4} r e f l u x R - B r + A g B r + C O_{2}$
General equation
So the products are $C_{6} H_{5} B r + A g B r + C O_{2}$

Suggest Corrections

Similar questions

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Predict the order of reactivity of the following compounds in SN1 and SN2 reactions

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