C6H5N2-Cl-X-N2-HCl-H3PO3The compound X is -

H_3PO_2 is the reagent that converts N^+_2Cl^ group into H. During this process nbsp; N_2 and HCl gases are released. The reaction is as follows: Hence, the ...

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Byju's Answer

Standard XII

Chemistry

Beta Elimination

C6H5N2+Cl-X+N...

Question

$C_{6} H_{5} N_{2}^{+} C l^{-} H_{3} P O_{2} - --- \to H_{2} O X + N_{2} ↑ + H C l + H_{3} P O_{3}$

The compound X is :

C_{6} H_{5} C l

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C_{6} H_{5} N H N H_{2}

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C_{6} H_{6}

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C_{6} H_{5} N O_{2}

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Solution

The correct option is C $C_{6} H_{6}$
$H_{3} P O_{2}$ is the reagent that converts $N_{2}^{+} C l^{-}$ group into H. During this process $N_{2}$ and $H C l$ gases are released.

The reaction is as follows:
Hence, the correct answer is option (c).

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Similar questions

Q. Iodobenzene is prepared from aniline

(C_{6} H_{5} N H_{2})

in a two step process as shown here:

C_{6} H_{5} N H_{2} + H N O_{2} + H C l \to C_{6} H_{5} N_{2}^{+} C l^{-} + 2 H_{2} O

C_{6} H_{5} N_{2}^{+} C l^{-} + K l \to C_{6} H_{5} I + N_{2} + K C l

In an actual preparation, 9.30 g of aniline was converted to 12.32 g of iodobenzene. The percentage yield of iodobenzene is:

C_{6} H_{5} N_{2} C l H_{3} P O_{2} - --- \to H_{2} O X + N_{2} + H C l

The compound X is:

Q. Iodobenzene

(C_{6} H_{5} I)

is prepared from aniline

(C_{6} H_{5} N H_{2})

in a two step process as shown below:

C_{6} H_{5} N H_{2} + H N O_{2} + H C l \to C_{6} H_{5} N_{2}^{+} C l^{-} + 2 H_{2} O

C_{6} H_{5} N_{2}^{+} C l^{-} + K I \to C_{6} H_{5} I + N_{2} + K C l

In an actual preparation,

9.30

g of aniline was converted to

16.32

g of iodobenzene. The percentage yield of iodobenzene is:

C_{6} H_{5} N_{2}^{\oplus} C l^{⊝} C u_{2} C l_{2} - --- \to H C l C_{6} H_{5} C l + N_{2}

Q. Diazonium salt decomposes as

C_{6} H_{5} N_{2}^{\oplus} C l^{⊖} \to C_{6} H_{5} C l + N_{2}

0^{0}

C, the evolution of

N_{2}

becomes two times faster when the initial concentration of the salt is doubled. Thus, it is :

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C6H5N+2Cl−H3PO2−−−−→H2OX+N2↑+HCl+H3PO3 The compound X is :

The correct option is C C6H6H3PO2 is the reagent that converts N+2Cl− group into H. During this process N2 and HCl gases are released. The reaction is as follows: Hence, the correct answer is option (c).

$C_{6} H_{5} N_{2}^{+} C l^{-} H_{3} P O_{2} - --- \to H_{2} O X + N_{2} ↑ + H C l + H_{3} P O_{3}$

The compound X is :

The correct option is C $C_{6} H_{6}$
$H_{3} P O_{2}$ is the reagent that converts $N_{2}^{+} C l^{-}$ group into H. During this process $N_{2}$ and $H C l$ gases are released.

The reaction is as follows:
Hence, the correct answer is option (c).