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Byju's Answer

Standard XII

Chemistry

Fluorides of Xenon

C 8 H 10 A un...

Question

$C_{8} H_{10}$ (A) undergo oxidative cleavage with one mole of $O_{3}$ in presence of $H_{2} O$ and forms $C_{3} H_{5} C O O H$ (B). Thus, A and B respectively are

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Both (a) and (b)

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None of the above

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Solution

The correct option is C Both (a) and (b)

An alkyne is more reactive than an alkene towards oxidation, therefore for one mole of an ozone, only alkyne will react. Also the formation of $- C O O H$ implies that there is an oxidation of alkyne.

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Q. Question 57
An organic compound A on heating with concentrated

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forms a compound B which on an addition of one mole of hydrogen in presence of

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A

and

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undergoes calcination to form a solid,

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and

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undergoes roasting to form a solid and a gas

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A

and

B

are two ores of copper.

A

undergoes calcination to form a solid,

C O_{2 (g)}

and

O_{2 (g)}

B

undergoes roasting to form a solid and a gas

C

which turns acidified

K_{2} C r_{2} O_{7}

to green solution.

B

also reacts with dil

H C l

to form a solid and gas

D

which turns lead acetate solution black.

D

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to form colloidal sulphur in the presence of moisture.

The copper ores

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and

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respectively are:

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C8H10 (A) undergo oxidative cleavage with one mole of O3 in presence of H2O and forms C3H5COOH (B). Thus, A and B respectively are

The correct option is C Both (a) and (b) An alkyne is more reactive than an alkene towards oxidation, therefore for one mole of an ozone, only alkyne will react. Also the formation of −COOH implies that there is an oxidation of alkyne.

$C_{8} H_{10}$ (A) undergo oxidative cleavage with one mole of $O_{3}$ in presence of $H_{2} O$ and forms $C_{3} H_{5} C O O H$ (B). Thus, A and B respectively are

The correct option is C Both (a) and (b)

An alkyne is more reactive than an alkene towards oxidation, therefore for one mole of an ozone, only alkyne will react. Also the formation of $- C O O H$ implies that there is an oxidation of alkyne.