Question

C and D are the children of A&B, who are married to each other. D is 5 years younger than C. Five years ago, A was twice as old as C. The current age of B is the average of A and C’s ages. If the average age of all of them is 34 years, find the current age of D?

• A. 18
• B. 21
• C. 22
• D. 27

Answer 1

The correct option is C 22

Let the present age of each of them be the letters themselves.

Present age of D= C-5

Presnt age of A will be 2(C-5)+5

=2C-5 and the present age of B will be (C+2C-5)/2 = (3C-5)/2

Average age of members =34

C+C-5+2C-5+(3C-5)/2=34x4

4C+(3C-5)/2= 146

11C= 297

C=27

D= 27-5=22

Option (C)