c) $C H_{3} C O C H_{3}$
$Z n - H C I / c o n c H C I ⟶$
Account the following :

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Solution

This reaction is clemmenson reduction, which is used to reduce carbonyl to alkene.

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Z n + H C l

H C I + N a O H

A g^{+} (a q) + C l^{-} (a q)

- {coch}_{2} - t o - C H_{2} - C H_{2} -

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I. $(C H_{3} C O O)_{2} C a △ - \to$ A II. $C H_{3} C O_{2} H H I - -- \to R e d P$ B III. $2 C H_{3} C O_{2} H P_{4} O_{10} - -- \to$ C

C_{7} H_{8}

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^{'} C^{'}

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(b) $H_{2} + O_{2} \to H_{2} O$

(d) $C O + O_{2} \to C O_{2}$

(e) $Z n + H C I \to Z n C l_{2} + H_{2}$

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