Question

$C{Cl}_{3}CHO+NO⟶CH{Cl}_3+NO+CO$

The rate of the reaction above is equal to rate $=k\left[C{Cl}_{3}CHO\right]\left[NO\right]$.

If the concentration is expressed in mol L ${}^{-1}$, find the unit of $k$?

• A. L mol ${}^{-1}$ s ${}^{-1}$
• B. mol L ${}^{-1}$ s ${}^{-1}$
• C. L ${}^2$ mol ${}^{-2}$ s ${}^{-1}$
• D. s ${}^{-1}$

Answer 1

The correct option is A L mol ${}^{-1}$ s ${}^{-1}$

Rate $=\frac{dx}{dt}=k\left[C{Cl}_{3}CHO\right]\left[NO\right]$

$k=\frac{dx}{dt\times k\left[C{Cl}_{3}CHO\right]\left[NO\right]}$

$=\frac{mol{L}^{-1}}{s^{-1}\times mol{L}^{-1}\times mol{L}^{-1}}$

$=L{mol}^{-1}{s}^{-1}$

Hence, the correct option is $\text{A}$