Question 66 (c)

Find the value of the given polynomial at a = -2 and b = 3.

$a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}$

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Solution

Given, a = -2 and b = 3
So, putting a = -2 and b = 3 in the given expression, we get
$a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3} = (- 2)^{3} + 3 (- 2)^{2} (3) + 3 (- 2) (3)^{2} + (3)^{3} = - 8 + 36 - 54 + 27 = 1$

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Similar questions

Find the value of $a^{3} - b^{3} - 3 a^{2} b + 3 a b^{2}$ , when a = 5 and b = 3.

(a + b)^{3} = a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

\frac{a^{3} + 3 {a b}^{2}}{b^{3} + 3 a^{2} b} = \frac{63}{62}

a : b

\frac{a}{b} + \frac{1}{2}

Which of the following is an expansion of the identity ${(a - b)}^{3}$ ?

(a + b)^{3} = a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

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