CH3Br+KCN(alc.)⟶XReduction−−−−−−−−−−−−→Na+C2H5OHY What is Y in the series?
A
CH3CN
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B
C2H5CN
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C
C2H5NH2
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D
CH3NH2
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Solution
The correct option is CC2H5NH2 (c) Y is ethyl amine obtained by the reduction of acetonitrile (X). CH3Br+KCN(alc.)⟶CH3CNX CH3CH2NH2YNa/C2H5OH←−−−−−−−−−−−−Reduction