Question

C is a point on the line segment joining A(-3, 4) and B (2, 1) such that AC = 2 BC then coordinates of C are

• A. $\left(\frac{1}{3},2\right)$
• B. $\left(2,\frac{1}{3}\right)$
• C. $\left(2,7\right)$
• D. $\left(7,2\right)$

Answer 1

The correct option is A $\left(\frac{1}{3},2\right)$

AC = 2 BC

$\frac{AC}{BC}=\frac{2}{1}$

$x=\frac{2x^2+1\times \left(-3\right)}{1+2}=\frac{4-3}{3}=\frac{1}{3}$

$y=\frac{2\times 1+1\times 4}{2+1}=\frac{2+4}{3}=2$

$C\left(\frac{1}{3},2\right)$