C is the centre of an equilateral triangle PQR. f1,f2 and f3 are the three forces acting along the sides as shown. For the total torque about C to be zero,
A
f3=(f1+f2)2
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B
f3=(f1+f2)4
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C
f3=f1+f2
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D
f3=f1−f2
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Solution
The correct option is Cf3=f1+f2 Both f1 and f2 exert counter-clockwise torque on the on the triangle about point O while f3 exerts clockwise torque about point O. The perpendicular distances from point O on the forces are equal by symmetry. Let the distance be l. ∴f1l+f2l−f3l=0 ⇒f1+f2=f3