Question

Question 16(c)

The present age of the father is 42 years and that of his son is 14 years. Find the ratio of:

Age of father after 10 years to the age of son after 10 years.

Answer 1

Age of father after 10 years = 42 + 10 = 52 years

Age of son after 10 years = 14 + 10 = 24 years

Therefore, ratio of their ages after 10 years

= $\frac{52}{24}=\frac{13}{6}=13:6$ [Dividing numerator and denominator by HCF of 52 and 24 i.e. 4]