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Question

C:x2+y2=9, E:x29+y24=1, L:y=2x

Equation of the diameter of the ellipse E conjugate to the diameter represented by L is :

A
9x+2y=0
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B
2x+9y=0
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C
4x+9y=0
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D
4x9y=0
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Solution

The correct option is B 2x+9y=0
Let y=mx be the diameter conjugate to the diameter L:y=2x of the ellipse E then,
2m=49 (mm=b2a2)
m=29 and the equation of the conjugate diameter is
y=29x or 2x+9y=0

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