C2O2−4 is a weak ligand but acts as a strong ligand in K3[Co(C2O4)3] and induces the pairing of electrons against Hund's rule. Why?
For the complex K3[Co(C2O4)3]
Let consider the oxidation state of Co=x
Charge on oxalato ion =−2
Charge on Potassium ion =+1
3(+1)+x+3(−2)=0
x=6−3
x=+3
So, the oxidation state of Cobalt is +3. When central metal is present in +3 oxidation state, oxalate ligands acts as strong ligand and cause pairing of electrons of d - orbital which leads to the formation of the inner orbital complex with d2sp3 hybridization.