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Question

C2O24 is a weak ligand but acts as a strong ligand in K3[Co(C2O4)3] and induces the pairing of electrons against Hund's rule. Why?

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Solution

For the complex K3[Co(C2O4)3]

Let consider the oxidation state of Co=x

Charge on oxalato ion =2

Charge on Potassium ion =+1

3(+1)+x+3(2)=0

x=63

x=+3

So, the oxidation state of Cobalt is +3. When central metal is present in +3 oxidation state, oxalate ligands acts as strong ligand and cause pairing of electrons of d - orbital which leads to the formation of the inner orbital complex with d2sp3 hybridization.


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