C₆H₅NO₂ was electrolysed into C₆H₅NH₂ by using 10A current for 20 seconds. If the current efficiency is 50%, find out the weight of nitrobenzene consumed.

Open in App

Solution

C6H5NO2+ 6H+ + 6e = C6H5NH2 + 2H2O
N3+ + 6e =N3–
So,
Eq. wt. of nitrobenzene = M/6=123/6=20.5
Current =10×50%
= 10×.5
w = Eit/96500
Or
W= (20.5×10×.5×20)/96500
=0.0212 g

Suggest Corrections

Similar questions

Q. The equivalent weight of nitrobenzene in the reaction:

C_{6} H_{5} N O_{2} \to C_{6} H_{5} N H_{2}

is:

Q. The energy consumed if the potential drop across the cell is

3.0 V

and

12.3

g of nitrobenzene is reduced to aniline, with current efficiency for the process be 50%, will be:

Q. If

9 g m H_{2} O

is electrolysed completely with the current of

50

% efficiency then :

Calculate the quantity of electricity that would be required to reduce 12.3 g of nitrobenzene to aniline, if current efficiency is 50% if the potential drops across the cell are 3.0 volt, how much energy will be consumed?

Q. Nitrobenzene

(C_{6} H_{5} N O_{2})

can be reduced to aniline

(C_{6} H_{5} N H_{2})

by electrolytic reduction. The equivalent mass of nitrobenzene will be equal to

(\frac{m o l e c u l a r m a s s}{n})

. What is the value of

n

Join BYJU'S Learning Program

C6H5NO2 was electrolysed into C6H5NH2 by using 10A current for 20 seconds. If the current efficiency is 50%, find out the weight of nitrobenzene consumed.

C6H5NO2+ 6H+ + 6e = C6H5NH2 + 2H2O N3+ + 6e =N3– So, Eq. wt. of nitrobenzene = M/6=123/6=20.5 Current =10×50% = 10×.5 w = Eit/96500 Or W= (20.5×10×.5×20)/96500 =0.0212 g

C₆H₅NO₂ was electrolysed into C₆H₅NH₂ by using 10A current for 20 seconds. If the current efficiency is 50%, find out the weight of nitrobenzene consumed.

C6H5NO2+ 6H+ + 6e = C6H5NH2 + 2H2O
N3+ + 6e =N3–
So,
Eq. wt. of nitrobenzene = M/6=123/6=20.5
Current =10×50%
= 10×.5
w = Eit/96500
Or
W= (20.5×10×.5×20)/96500
=0.0212 g