Ca2B6O11-Na2CO3 A-B-CaCO3A-CO2 - B-Na2CO3SolutionB- Conc- HCI - NaCI-Acid - H2OC D Acid CD-CuSO4 Blue colouredE compoundcompound E is -

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Ca2B6O11+Na2C...

Question

$C a_{2} B_{6} O_{11} + N a_{2} C O_{3} F u s e d - -- \to (A) + (B) + C a C O_{3} (A) + C O_{2} \to (B) + N a_{2} C O_{3} Solution (B) + C o n c . H C I \to N a C I + A c i d ↓ H_{2} O (C) S t r o n g l y - ---- \to h e a t e d (D) Acid (C) (D) + C u S O_{4} H e a t e d - ---- \to i n f l a m e Blue coloured (E) compound compound (E) is -$

$C u_{2} O$

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$C u S$

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$C u S O_{3}$

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$C u (B O_{2})_{2}$

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Solution

The correct option is D
$C u (B O_{2})_{2}$

Compound (A) is - $N a B O_{2}$
Compound (B) is - $N a_{2} B_{4} O_{7}$
Compound (C) is - $H_{3} B O_{3}$
Compound (D) is - $B_{2} O_{3}$
Compound (E) is - $C u (B O_{2})_{2}$

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Similar questions

Q. Match the following:

Column A Types of chemical reaction	Column B Chemical equations
(a) Combination reaction	(i) $C a C O_{3} A \to C a O + C O_{2}$
(b) Decomposition reaction	(ii) $2 H_{2} O E l e c t r i c i t y - ----- \to 2 H_{2} + O_{2}$
(c) Displacement reaction	(iii) $C a O + C O_{2} \to C a C O_{3}$
(d) Analysis reaction	(iv) $F e (s) + C u S O_{4} (a q .) \to F e S O_{4} (a q) + C u (s)$

Q. The reaction of formic acid with concentrated

H_{2} S O_{4}

gives

Q. the correct increasing order of acidity of

C O_{2}, H_{2} O

and

H_{2} O_{2}

is:

$C a_{2} B_{6} O_{11} + N a_{2} C O_{3} F u s e d - -- \to (A) + (B) + C a C O_{3} (A) + C O_{2} \to (B) + N a_{2} C O_{3} Solution (B) + C o n c . H C I \to N a C I + A c i d ↓ H_{2} O (C) S t r o n g l y - ---- \to h e a t e d (D) Acid (C) (D) + C u S O_{4} H e a t e d - ---- \to i n f l a m e Blue coloured (E) compound compound (E) is -$

Q. Find A and B in the following reaction.

C H_{3} C H_{2} O H + O_{2} \to A + B +

Heat and light

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Ca2B6O11+Na2CO3Fused−−−→(A)+(B)+CaCO3(A)+CO2→(B)+Na2CO3Solution(B)+Conc.HCI→NaCI+Acid ↓H2O(C)Strongly−−−−−→heated (D) Acid(C)(D)+CuSO4Heated−−−−−→inflameBlue coloured(E) compoundcompound (E) is -

The correct option is D Cu(BO2)2 Compound (A) is - NaBO2 Compound (B) is - Na2B4O7 Compound (C) is - H3BO3 Compound (D) is - B2O3 Compound (E) is - Cu(BO2)2

The correct option is D
$C u (B O_{2})_{2}$

Compound (A) is - $N a B O_{2}$
Compound (B) is - $N a_{2} B_{4} O_{7}$
Compound (C) is - $H_{3} B O_{3}$
Compound (D) is - $B_{2} O_{3}$
Compound (E) is - $C u (B O_{2})_{2}$