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Question

Ca2B6O11Δ−→[X]+CaCO3+NaBO2 (unbalanced equation) Which of the following is/are correct choice(s) for [X]?

A
The structure of anion of crystalline [X] has one boron atom sp3 hybridized and other three boron atoms sp2 hybridized
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B
X with NaOH(aq) gives a compound which on reaction with hydrogen peroxide in alkaline medium yields a compound used as the brightener in soaps
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C
Hydrolysis of [X] with HCl or H2SO4 yields a compound which on reaction with HF gives fluoroboric acid
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D
[X] on heating with chromium salts in oxidizing flame gives green colored bead
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Solution

The correct options are
B X with NaOH(aq) gives a compound which on reaction with hydrogen peroxide in alkaline medium yields a compound used as the brightener in soaps
C Hydrolysis of [X] with HCl or H2SO4 yields a compound which on reaction with HF gives fluoroboric acid
D [X] on heating with chromium salts in oxidizing flame gives green colored bead
The compound X is borax (Na2B4O7). It is prepared by boiling finely powdered colemanite mineral (Ca2B6O11) with sodium carbonate solution.

Ca2B6O11+2Na2CO32CaCO3+Na2B4O7+2NaBO2

The statements (B), (C) and (D) are correct. The statement (A) is incorrect.

(A) The structure of anion of crystalline [X] has two boron atoms sp3 hybridized and other two boron atoms sp2 hybridized.

(B) X with NaOH(aq), gives sodium metaborate NaBO2 which on reaction with hydrogen peroxide in alkaline medium yields hexahydrate sodium tetraaquadiperoxoborate (III).

2NaBO2+2H2O2+6H2ONa2[B2(O2)2(OH)4]6H2O

(C) Hydrolysis of [X] with HCl or H2SO4 yields boric acid which on reaction with HF gives fluoroboric acid.

Na2B4O7+H2SO4Na2SO4+H2B4O7
H2B4O7+5H2O4H3BO3
H3BO3+4HFH[BF4]+3H2O

(D) [X] on heating with chromium slats in oxidizing flame gives green colored bead.
Cr2O)3+3B2O32Cr(BO2)3(chromium metaborate green)
This is borax bead test.

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