The correct options are
B X with
NaOH(aq) gives a compound which on reaction with hydrogen peroxide in alkaline medium yields a compound used as the brightener in soaps
C Hydrolysis of [
X] with
HCl or
H2SO4 yields a compound which on reaction with
HF gives fluoroboric acid
D [
X] on heating with chromium salts in oxidizing flame gives green colored bead
The compound X is borax
(Na2B4O7). It is prepared by boiling finely powdered colemanite mineral
(Ca2B6O11) with sodium carbonate solution.
Ca2B6O11+2Na2CO3→2CaCO3+Na2B4O7+2NaBO2
The statements (B), (C) and (D) are correct. The statement (A) is incorrect.
(A) The structure of anion of crystalline [X] has two boron atoms sp3 hybridized and other two boron atoms sp2 hybridized.
(B) X with NaOH(aq), gives sodium metaborate NaBO2 which on reaction with hydrogen peroxide in alkaline medium yields hexahydrate sodium tetraaquadiperoxoborate (III).
2NaBO2+2H2O2+6H2O→Na2[B2(O2)2(OH)4]∙6H2O
(C) Hydrolysis of [X] with HCl or H2SO4 yields boric acid which on reaction with HF gives fluoroboric acid.
Na2B4O7+H2SO4→Na2SO4+H2B4O7
H2B4O7+5H2O→4H3BO3
H3BO3+4HF→H[BF4]+3H2O
(D) [X] on heating with chromium slats in oxidizing flame gives green colored bead.
Cr2O)3+3B2O3→2Cr(BO2)3(chromium metaborate green)
This is borax bead test.