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Byju's Answer
Standard XII
Chemistry
Gibbs Free Energy & Spontaneity
CaCO3s→ CaOs+...
Question
C
a
C
O
3
(
s
)
→
C
a
O
(
s
)
+
C
O
2
(
g
)
Δ
H
=
+
180
K
J
If entropies of limestone, lime and carbon dioxide are
93
,
39
and
213
J
/
m
o
l
/
K
. Then
Δ
S
t
o
t
a
l
in
J
K
−
1
at
300
K
is:
A
159
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B
−
441
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C
700
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D
−
650
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Solution
The correct option is
A
159
△
S
t
o
t
a
l
=
△
S
p
r
o
d
u
c
t
s
−
△
S
r
e
a
c
t
a
n
t
s
=
△
S
C
a
O
+
△
S
C
O
2
−
△
S
C
a
C
O
3
=
39
+
213
−
93
=
159
Suggest Corrections
0
Similar questions
Q.
Quick lime (CaO) is produced by heating limestone
(
C
a
C
O
3
)
to drive off
C
O
2
gas.
C
a
C
O
3
(
s
)
→
C
a
O
(
s
)
+
C
O
2
(
g
)
,
Δ
H
o
=
180
K
J
,
Δ
S
o
=
150
J
/
K
Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option.
Q.
Quick lime
(
C
a
O
)
is produced by heating limestone
(
C
a
C
O
3
)
to drive off
C
O
2
gas.
C
a
C
O
3
(
s
)
→
C
a
O
(
s
)
+
C
O
2
(
g
)
,
Δ
H
0
=
180
K
J
;
Δ
S
0
=
150
J
/
K
.
Assuming the variation of enthalpy change and entropy change with temperature to be negligible, choose the incorrect option(s).
Q.
In conversion of limestone to lime,
C
a
C
O
3
(
s
)
→
C
a
O
(
s
)
+
C
O
2
(
g
)
; the values of
Δ
H
0
and
Δ
S
0
are + 179.1 kJ/mol and 160.2J/K respectively, at 298K and 1 bar. Above what temperature, conversion of limestone to lime will be spontaneous (assuming that
Δ
H
0
and
Δ
S
0
do not change with temperature)?
Q.
For the reaction
C
a
C
O
3
(
s
)
→
C
a
O
(
s
)
+
C
O
2
(
g
)
(at
1240
K and
1
atm.)
Δ
H
=
176
k
J
/
m
o
l
, then
Δ
E
will be:
Q.
For
C
a
C
O
3
(
s
)
→
C
a
O
(
s
)
+
C
O
2
(
g
)
at
977
o
C
,
Δ
H
=
174
k
J
/
m
o
l
; then
Δ
E
is:
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