Balancing Chemical Equations by Partial Equation Method
CaCO 3 +2HCl→...
Question
CaCO3+2HCl→CaCl2+H2O+CO2 The volume of CO2 gas formed when 2.5 g calcium carbonate are dissolved in excess hydrochloric acid at 0∘C and 1 atm pressure is :
(1 mole of any gas at 0∘C and 1 atm pressure occupies 22.414)
A
1.12 L
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B
56.0 L
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C
0.28 L
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D
0.56 L
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Solution
The correct option is C 0.56 L No. of mole of calcium carbonate=givenwt.molarmass=2.5100=0.025
1 mole of carbon dioxide gas has volume = 22.414 L
0.025 mol of carbon dioxide= 22.414 × 0.025= 0.56 L