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Balancing Chemical Equations by Partial Equation Method

CaCO 3 +2HCl→...

Question

${C a C O}_{3} + 2 H C l \to {C a C l}_{2} + H_{2} O + {C O}_{2}$
The volume of ${C O}_{2}$ gas formed when 2.5 g calcium carbonate are dissolved in excess hydrochloric acid at $0^{\circ} C$ and 1 atm pressure is :
(1 mole of any gas at $0^{\circ} C$ and 1 atm pressure occupies 22.414)

1.12 L

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56.0 L

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0.28 L

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0.56 L

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Solution

The correct option is C 0.56 L
No. of mole of calcium carbonate= $\frac{g i v e n w t .}{m o l a r m a s s} = \frac{2.5}{100} = 0.025$
1 mole of carbon dioxide gas has volume = 22.414 L
0.025 mol of carbon dioxide= 22.414 $\times$ 0.025= 0.56 L

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