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Question

CaCO3 is 90% pure. Volume of CO2 collected at STP when 10 g of CaCO3 is decomposed is:

A
2.016 litres
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B
1.008 litres
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C
10.08 litres
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D
20.16 litres
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Solution

The correct option is A 2.016 litres

Note that the gas produced is CO2
Equation:
CaCO3CaO+CO2
1 mol CaCO3 produces 1 mol CO2

You have 90100×10=9g pure CaCO3

Molar mass CaCO3= 100g/mol
9gCaCO3=9100=0.09molCaCO3
This will produce 0.09 mol CO2
At STP 1mol=22.4L
0.09mol=0.09×22.4=2.016L

Hence the volume of the CO2 collected at STP when is decomposed is = 2.0L


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