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Standard X

Chemistry

Electrolysis and Electrolytes

Cadmium amalg...

Question

Cadmium amalgam is prepared by electrolysis of the solution of ${C d C l}_{2}$ using a mercury cathode. How long should a current of $4 A$ be passed in order to prepare $10$ by mass Cd in Cd Hg amalgam on the cathode of 4.5 g Hg? (atomic mass of Cd = 112)

400 s e c

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215.40 s e c

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861.6 s e c

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430.8 s e c

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Solution

The correct option is A $400 s e c$
$∵ W = z . i . t$
$10 = \frac{E}{F} \times i . t$ $⟹ t = {\frac{10 \times 96500}{(112 / 2) \times 4}}$ $s e c$
$⟹ t = 4308.03$ $s e c$

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Similar questions

Q. Cadmium amalgam is prepared by electrolysis of a solution of

C d C l_{2}

using a mercury cathode. Find how long a current of

5

ampere should be passed in order to prepare

12

C d - H g

amalgam on a cathode of

2 g

mercury. At. mass of

C d = 112.40

Q. Cd amalgam is prepared by electrolysis of a solution of

C d C l_{2}

using a mercury cathode. Find how long (in minutes) should a current of 5 ampere is passed in order to prepare 12%

C d - H g

amalgam on a cathode of 2.56 g mercury? At. wt. of Cd = 112.40.

C d

amalgam is prepared by electrolysis of a solution

C a C l_{2}

using a mercury cathode. The time (in a sec) for which a current of

5 A

should be passed in order to prepare

12

C d - H g

amalgam on a cathode of

2 g H g

is ______

Atomic weight of

C d = 112.4

. (write the value to the nearest integer)

Z n

Amalgam is prepared by the electrolysis of aqueous

Z n C l_{2}

using

H g

cathode (9 gm). How much current should be passed through

Z n C l_{2}

solution for 1000 seconds to prepare a

Z n

amalgam with 25%

Z n

by weight ?

(Z n

atomic weight

= 65.4)

Z n

amalgam is prepared by the electrolysis of aqueous

Z n C l_{2}

using

H g

cathode (9g). How much current is to be passed through

Z n C l_{2}

solution for 1000 seconds to prepare a

Z n

amalgam with 25%

Z n

by weight? (

Z n =

65.4)

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Cadmium amalgam is prepared by electrolysis of the solution of CdCl2 using a mercury cathode. How long should a current of 4A be passed in order to prepare 10 by mass Cd in Cd Hg amalgam on the cathode of 4.5 g Hg? (atomic mass of Cd = 112)

The correct option is A 400 sec∵W=z.i.t10=EF×i.t ⟹t={10×96500(112/2)×4} sec⟹t=4308.03 sec

Cadmium amalgam is prepared by electrolysis of the solution of ${C d C l}_{2}$ using a mercury cathode. How long should a current of $4 A$ be passed in order to prepare $10$ by mass Cd in Cd Hg amalgam on the cathode of 4.5 g Hg? (atomic mass of Cd = 112)

The correct option is A $400 s e c$
$∵ W = z . i . t$
$10 = \frac{E}{F} \times i . t$ $⟹ t = {\frac{10 \times 96500}{(112 / 2) \times 4}}$ $s e c$
$⟹ t = 4308.03$ $s e c$