Caesium chloride is formed according to the following equation:
Cs(s)+0.5Cl2(g)⟶CsCl(s)
The enthalpy of sublimation of Cs, enthalpy of dissociation of chlorine, ionization energy of Cs and electron affinity of chlorine are 81.2,243.0,375.7 and −348.3kJ ol−1. The energy change involved in the formation of CsCl is 388.6 kJ.mol−1. Calculate the lattice energy of CsCl.