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Stoichiometric Calculations

CaF2 precipit...

Question

$C a F_{2}$ precipitated is :

52.63 kmol

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263.16 kmol

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35.71 kmol

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26.32 kmol

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Solution

The correct option is A 52.63 kmol
$F_{2} + 2 N a O H ⟶ \frac{1}{2} O_{2} + 2 N a F + H_{2} O$
$2 N a F + C a O + H_{2} O ⟶ C a F_{2} + 2 N a O H$
According to process,
$F_{2}$ $C a F_{2}$
$1$ mole $1$ mole
$\frac{2000}{38} = 52.63$ kmol $52.63$ kmol
Hence, $C a F_{2}$ precipitated is $52.63$ kmol.

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