Caffeine has $M o l . W t = 194$ . It contains $28.9 %$ by mass of Nitrogen in one molecule of caffeine.

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Solution

Molar mass of caffeine = $194 u$
N present in one molecule of caffeine = $28.9$ % of $194$ $= \frac{28.9}{100} \times 194 = 56 u$
Mass of one N atom = $14 u$
Hence $14 u = 1 N$ atom
$56 u = \frac{56}{14}$ N atom = $4 N$ atom

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Caffeine has Mol.Wt=194. It contains 28.9% by mass of Nitrogen in one molecule of caffeine.

Molar mass of caffeine = 194uN present in one molecule of caffeine = 28.9 % of 194 =28.9100×194=56uMass of one N atom = 14uHence 14u=1N atom56u=5614 N atom = 4N atom

Caffeine has $M o l . W t = 194$ . It contains $28.9 %$ by mass of Nitrogen in one molecule of caffeine.

Molar mass of caffeine = $194 u$
N present in one molecule of caffeine = $28.9$ % of $194$ $= \frac{28.9}{100} \times 194 = 56 u$
Mass of one N atom = $14 u$
Hence $14 u = 1 N$ atom
$56 u = \frac{56}{14}$ N atom = $4 N$ atom