Calcium carbonate 10 g reacts with aqueous HCl 0-3 mol according to the reaction- CaCO3s-2HCl aq - CaCl2 aq -CO2 g -H2O l - The number of moles of CaCl2 formed in the reaction is-

The correct option is A 0.1 molThe balanced reaction is CaCO_3(s)+2HCl ( aq )→ CaCl_2 ( aq )+CO_2 ( g )+H_2O ( l ) . 10 g calcium carbonate ...

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Byju's Answer

Standard XII

Chemistry

Properties of Water

Calcium carbo...

Question

Calcium carbonate ( $10$ g) reacts with aqueous $H C l$ ( $0.3$ mol) according to the reaction, $C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$ .
The number of moles of $C a C l_{2}$ formed in the reaction is:

0.1

mol

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0.2

mol

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0.01

mol

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0.066

mol

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Solution

The correct option is A $0.1$ mol
The balanced reaction is $C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$ .
$10$ g calcium carbonate corresponds to $\frac{10}{100} = 0.1$ mole (Molecular weight of $C a C O_{3}$ = $100$ g/mol).
It will react with $0.2$ mol $H C l$ .
However, $0.3$ mol $H C l$ is present.
Hence, calcium carbonate is the limiting reagent.
$0.1$ mol of calcium carbonate will form $0.1$ mol of calcium chloride.

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Similar questions

Q. Calcium carbonate reacts with aqueous

H C l

to give

{C a C l}_{2}

and

{C O}_{2}

according to the reaction,

{C a C O}_{3} (s) + 2 H C l (a q) \to {C a C l}_{2} (a q) + {C O}_{2} (g) + H_{2} O (l)

What mass of

{C a C O}_{3}

is required to react completely with 25 mL of 0.75 M

H C l

Q. Calcium carbonate reacts with aqueous HCl to give

C a C l_{2}

and

C O_{2}

according to the reaction:

C a C O_{3} (s) + H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)

When 250 mL of 0.76 M HCl reacts with 1000 g of

C a C O_{3}

, calculate the number of moles of

C a C l_{2}

formed:

Calcium carbonate reacts with aqueous $HCl$ to give ${CaCl}_{2}$ and ${CO}_{2}$ according to the reaction given below

$\underset{Calcium Carbonate}{{CaCO}_{3} (s)} + \underset{Hydrochloric acid}{2 HCl (aq)} ⟶ \underset{Calcium Chloride}{{CaCl}_{2} (aq)} + \underset{Carbon dioxide}{{CO}_{2} (g)} + \underset{Water}{H_{2} O (l)}$

What mass of ${CaCO}_{3}$ is required to react completely with 25 mL of 0.75 M HCl?

1) 0.6844

2) 0.9375

3) 0.4265

4) 0.2785

Calcium carbonate reacts with aqueous HCl to give $C a C l_{2}$ and $C O_{2}$ according to the reaction given below

$C a C O_{3} (s) + 2 H C l (a q) ⟶ C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$

What mass of $C a C l_{2}$ will be formed when 250 mL of 0.76 M HCl reacts with 1000 g of $C a C O_{3}$ ? Name the limiting reagent. Calculate the number of moles of $C a C l_{2}$ formed in the reaction.

Q. Calcium carbonate reacts with aqueous

H C I

to give

C a C l_{2}

and

{C O}_{2}

according to the reactions:

C a {C O}_{3 (s)} + 2 H C l_{(a q)} \to C a {C l}_{2 (a q)} + {C O}_{2 (g)} + H_{2} O

What mass of

C a C O_{3}

is required to completely react with

25 m L

0.75 M H C l

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Calcium carbonate (10 g) reacts with aqueous HCl (0.3 mol) according to the reaction, CaCO3(s)+2HCl(aq)→CaCl2(aq)+CO2(g)+H2O(l). The number of moles of CaCl2 formed in the reaction is:

Calcium carbonate ( $10$ g) reacts with aqueous $H C l$ ( $0.3$ mol) according to the reaction, $C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$ .
The number of moles of $C a C l_{2}$ formed in the reaction is: