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Question

Calcium carbonate decomposes completely, on heating, into lime (CaO) and carbon dioxide (CO2). 1 kg of calcium carbonate is completely decomposed by heat, when 560 g of lime are obtained. How much quantity of carbon dioxide in grams, moles and litres at NTP is produced in the process ?

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Solution

According to law of conservation of mass, Mass of lime + Mass of carbon dioxide = Mass of calcium carbonate
560 g + Mass of CO2 = 1000 g
Mass of CO2 =1000 - 560 = 440 g
Molecular mass of CO2 = 12 + 32 = 44 g (1 mole)
No. of moles in 440 g of CO2=44044=10
1 mole of CO2 occupies volume at NTP = 22.4 litre
10 moles of CO2 will occupy volume at NTP =22.4×10=224 litre

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