MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Mole Concept

Calcium carbo...

Question

Calcium carbonate decomposes on heating to form calcium oxide and carbon dioxide. According to law of conservation of mass, if $5.6 g m s$ of calcium oxide and $4.4 g m s$ of carbon dioxide are formed, how much calcium carbonate was taken?

A

15g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

10g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

12g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 10g
According to the law of conversation of mass,
Total mass of reactant $=$ total mass of products
$= 5.6 + 4.4$
$= 10$ g
Mass of $C a C O_{3} = 10$ g

Suggest Corrections

thumbs-up

6

Similar questions

Q. 2 kg of calcium carbonate (lime stone) decomposes completely on heating, forming calcium oxide (lime) and carbon dioxide. If 880 grams of carbon dioxide is formed, what is the mass of calcium oxide formed?

Q. Balance the equation in which, calcium carbonate decomposes, on heating, to form calcium oxide and carbon dioxide

50 g

of an impure calcium carbonate sample decomposes on heating to give carbon dioxide and

22.4 g

calcium oxide. The percentage purity of calcium carbonate in the sample is:

Q. Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of

C O_{2}

will be obtained at STP by thermal decomposition of 50 g of

C a C O_{3}

?

Q. Calcium carbonate decomposes into calcium oxide and carbon dioxide. The reactant is:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Mole Concept

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon