Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of $C O_{2}$ will be obtained at STP by thermal decomposition of 50 g of $C a C O_{3}$ ?

1 L

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11.2 L

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44 L

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22.4 L

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Solution

The correct option is A 11.2 L
Chemical reaction involved is:

$C a C O_{3} \to C a O + C O_{2}$

Molar mass of $C a C O_{3} = 40 + 12 + 16 \times 3 = 100 g$

According to the balanced reaction $100 g$ of $C a C O_{3}$ produces 1 mol of $C O_{2}$ i.e. $22.4 L$ at STP.

$∴ 50 g C a C O_{3}$ will produce $\frac{22.4}{100} \times 50 = 11.2 L C O_{2}$ at STP.

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C a C O_{3} (s) \to C a O (s) + C O_{2} (g)

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Calcium carbonate decomposes on heating according to the equation:

$C a C O_{3}$ (s) $⟶$ CaO(s)+ $C O_{2}$

At STP, the volume of $C O_{2}$ obtained by thermal decomposition of 50g of $C a C O_{3}$ will be:

C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)

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G i v e n : C a C O_{3} \to C a O + C O_{2}

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