Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction - CaCO3s-2HClaq- CaCl2aq-CO2g-H2OlThe mass of CaCO3 which is required to react completely with 25 ml of 0-75 M HCl is-

The correct option is C 0.9375 g Eq. of CaCO_3 = Eq. of HCl.Eq. of HCl = 25 × 0.751000 Eq. of CaCO_3 = 2 × mass100 Mass of CaCO ...

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Standard XII

Chemistry

Reactivity Trends (Group 2)

Calcium carbo...

Question

Calcium carbonate reacts with aqueous HCl to give $C a C l_{2}$ and $C O_{2}$ according to the reaction - $C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$ The mass of $C a C O_{3}$ which is required to react completely with 25 ml of 0.75 M HCl is:

1.825 g

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0.9375 g

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1.8357 g

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0.46875 g

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Solution

The correct option is C $0.9375 g$
Eq. of $C a C O_{3}$ $=$ Eq. of HCl.

Eq. of HCl $= \frac{25 \times 0.75}{1000}$

Eq. of $C a C O_{3} = \frac{2 \times m a s s}{100}$

Mass of $C a C O_{3} = 0.9375 g$

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Similar questions

Calcium carbonate reacts with aqueous HCl to give CaCl₂ and CO₂ according to the reaction, CaCO₃₍_s₎ + 2 HCl₍_aq₎ → CaCl₂₍_aq₎ + CO₂₍_g) + H₂O₍_l₎

What mass of CaCO₃ is required to react completely with 25 mL of 0.75 M HCl?

Q. Calcium carbonate reacts with aqueous

H C l

to give

C a C l_{2} and C O_{2}

according to the raction,

C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)

.
The mass of

C a C O_{3}

is required to react compelety with

25

mL

0.75 M

HCI

is:

Calcium carbonate reacts with aqueous $HCl$ to give ${CaCl}_{2}$ and ${CO}_{2}$ according to the reaction given below

$\underset{Calcium Carbonate}{{CaCO}_{3} (s)} + \underset{Hydrochloric acid}{2 HCl (aq)} ⟶ \underset{Calcium Chloride}{{CaCl}_{2} (aq)} + \underset{Carbon dioxide}{{CO}_{2} (g)} + \underset{Water}{H_{2} O (l)}$

What mass of ${CaCO}_{3}$ is required to react completely with 25 mL of 0.75 M HCl?

1) 0.6844

2) 0.9375

3) 0.4265

4) 0.2785

Q. Calcium carbonate reacts with aqueous

H C I

to give

C a C l_{2}

and

{C O}_{2}

according to the reactions:

C a {C O}_{3 (s)} + 2 H C l_{(a q)} \to C a {C l}_{2 (a q)} + {C O}_{2 (g)} + H_{2} O

What mass of

C a C O_{3}

is required to completely react with

25 m L

0.75 M H C l

Calcium carbonate reacts with aqueuaq HCl to give calcium chloride and carbon dioxide according to the reaction .

CaCl2 (s) + 2HCl (aq.) = CaCl2 (aq) + CO2 (g) + H2O (l)

What mass of calcium carbonate is required to react completely with 25ml of 0.75M HCl?

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Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction -CaCO3(s)+2HCl(aq)→CaCl2(aq)+CO2(g)+H2O(l)The mass of CaCO3 which is required to react completely with 25 ml of 0.75 M HCl is:

The correct option is C 0.9375gEq. of CaCO3 = Eq. of HCl.Eq. of HCl =25×0.751000Eq. of CaCO3=2×mass100Mass of CaCO3=0.9375g

Calcium carbonate reacts with aqueous HCl to give $C a C l_{2}$ and $C O_{2}$ according to the reaction - $C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$ The mass of $C a C O_{3}$ which is required to react completely with 25 ml of 0.75 M HCl is:

The correct option is C $0.9375 g$
Eq. of $C a C O_{3}$ $=$ Eq. of HCl.

Eq. of HCl $= \frac{25 \times 0.75}{1000}$

Eq. of $C a C O_{3} = \frac{2 \times m a s s}{100}$

Mass of $C a C O_{3} = 0.9375 g$