Calcium carbonate reacts with aqueous HCl to give CaCl 2 and CO 2 according to the reaction- CaCO 3-2 HCl - CaCl 2- H 2 O What mass of CaCO 3 is required to react completely with 25 mL of 0-75 HCl -

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Standard XII

Chemistry

Grignard Reagents

Calcium carbo...

Question

Calcium carbonate reacts with aqueous HCl to give CaCl₂and CO₂according to the reaction, CaCO₃+ 2HCl --> CaCl₂+ H₂O

What mass of CaCO3 is required to react completely with 25mL of 0.75 HCl?

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Solution

No. Of moles of HCL used = Mass× Volume÷1000= 0.75×25÷1000
=0.01875
=0.019
No.of moles of CaCO3 to react with HCL=1÷2 ×no.of moles of HCL
=1÷2×0.019÷1000
=9.5×10 to the power -3
Mass of CaCO3 = no. Of moles of CaCO3 × molar mass
= 9.5×10to the power -3 × 100
= 0.95 g

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C a C l_{2}

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{C O}_{2}

according to the reactions:

C a {C O}_{3 (s)} + 2 H C l_{(a q)} \to C a {C l}_{2 (a q)} + {C O}_{2 (g)} + H_{2} O

What mass of

C a C O_{3}

is required to completely react with

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Calcium carbonate reacts with aqueous HCl to give CaCl₂ and CO₂ according to the reaction, CaCO₃₍_s₎ + 2 HCl₍_aq₎ → CaCl₂₍_aq₎ + CO₂₍_g) + H₂O₍_l₎

What mass of CaCO₃ is required to react completely with 25 mL of 0.75 M HCl?

Calcium carbonate reacts with aqueous $HCl$ to give ${CaCl}_{2}$ and ${CO}_{2}$ according to the reaction given below

$\underset{Calcium Carbonate}{{CaCO}_{3} (s)} + \underset{Hydrochloric acid}{2 HCl (aq)} ⟶ \underset{Calcium Chloride}{{CaCl}_{2} (aq)} + \underset{Carbon dioxide}{{CO}_{2} (g)} + \underset{Water}{H_{2} O (l)}$

What mass of ${CaCO}_{3}$ is required to react completely with 25 mL of 0.75 M HCl?

1) 0.6844

2) 0.9375

3) 0.4265

4) 0.2785

Q. Calcium carbonate reacts with aqueous HCl to give

C a C l_{2}

and

C O_{2}

according to the reaction -

C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)

The mass of

C a C O_{3}

which is required to react completely with 25 ml of 0.75 M HCl is:

Q. Calcium carbonate reacts with aqueous

H C l

to give

C a C l_{2} and C O_{2}

according to the raction,

C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)

.
The mass of

C a C O_{3}

is required to react compelety with

25

mL

0.75 M

HCI

is:

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Calcium carbonate reacts with aqueous HCl to give CaCl​​​2 and CO​​​​​2 according to the reaction, CaCO​​​3 + 2HCl --> CaCl​​​2 + H​​​​​2​​​​​O What mass of CaCO3 is required to react completely with 25mL of 0.75 HCl?

No. Of moles of HCL used = Mass× Volume÷1000= 0.75×25÷1000 =0.01875 =0.019 No.of moles of CaCO3 to react with HCL=1÷2 ×no.of moles of HCL =1÷2×0.019÷1000 =9.5×10 to the power -3 Mass of CaCO3 = no. Of moles of CaCO3 × molar mass = 9.5×10to the power -3 × 100 = 0.95 g

Calcium carbonate reacts with aqueous HCl to give CaCl₂and CO₂according to the reaction, CaCO₃+ 2HCl --> CaCl₂+ H₂O

What mass of CaCO3 is required to react completely with 25mL of 0.75 HCl?

No. Of moles of HCL used = Mass× Volume÷1000= 0.75×25÷1000
=0.01875
=0.019
No.of moles of CaCO3 to react with HCL=1÷2 ×no.of moles of HCL
=1÷2×0.019÷1000
=9.5×10 to the power -3
Mass of CaCO3 = no. Of moles of CaCO3 × molar mass
= 9.5×10to the power -3 × 100
= 0.95 g