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Question

Calcium carbonate reacts with aqueous HCl to give CaCl​​​2 and CO​​​​​2 according to the reaction, CaCO​​​3 + 2HCl --> CaCl​​​2 + H​​​​​2​​​​​O

What mass of CaCO3 is required to react completely with 25mL of 0.75 HCl?


Solution

No. Of moles of HCL used = Mass× Volume÷1000=  0.75×25÷1000
                         =0.01875
                         =0.019
No.of moles of CaCO3 to react with HCL=1÷2 ×no.of moles of HCL   
=1÷2×0.019÷1000
=9.5×10 to the power -3
Mass of CaCO3 = no. Of moles of CaCO3 × molar mass
                            = 9.5×10to the power -3 × 100
                            = 0.95 g

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