Question

Calcium imide on hydrolysis gives gas (B) which on oxidation by bleaching powder gives gas (C). Gas (C) on reaction with magnesium give compound (D) which on hydrolysis gives again gas (B). The compounds (B), (C) and (D) are respectively:

• A. $N{H}_3,N_2,M{g}_3{N}_2$
• B. $N_2,N{H}_3,MgNH$
• C. $N_2,N_2{O}_5,Mg(N{O}_3{)}_2$
• D. $N{H}_3,N{O}_2,Mg(N{O}_2{)}_2$

Answer 1

The correct option is A $N{H}_3,N_2,M{g}_3{N}_2$

$Ca\left(NH\right)+2H_{2}O⟶Ca(OH{)}_2+\underset{\left(B\right)}{N{H}_3\left(g\right)}$

$\underset{\left(B\right)}{2N{H}_3}+3CaOC{l}_2⟶\underset{\left(C\right)}{N_2\left(g\right)}+3CaC{l}_2+3H_{2}O$

$\underset{\left(C\right)}{N_2\left(g\right)}+3Mg⟶\underset{\left(D\right)}{M{g}_3{N}_2}$

$\underset{\left(D\right)}{M{g}_3{N}_2}+6H_{2}O⟶3Mg(OH{)}_2+\underset{\left(B\right)}{2N{H}_3\left(g\right)}$