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Question

Calculalte R,when R=A2+B2+2ABcosθ given that, A = 6 m, B = 8 m and angle is 600

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Solution

Given that,

Vector A=6m

Vector B=8m

Angle θ=600

Now, the resultant is

R=A2+B2+2ABcosθ

R=36+64+2×6×8×12

R=12.16m

Hence, the resultant is 12.16 m


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