Question

Calculate (1) The capacitive reactance, (2) Impedance of the circuit (3) Current flowing in the circuit.

Answer 1

Given : $R=160\Omega$
Also, $\tan \theta =\frac{3}{4}$
$⟹\cos \theta =\frac{4}{5}=0.8$
Using $\cos \theta =\frac{R}{Z}$
$\therefore$ Impedance of cicruit $Z=\frac{R}{cos\theta }=\frac{160}{0.8}=200\Omega$
Current flowing in the circuit $I=\frac{V}{Z}=\frac{220}{200}=1.1A$
Also using $Z^2=R^2+X_c^2$
$\therefore$ $X_c=\sqrt{Z^2-R^2}=\sqrt{(200{)}^2-(160{)}^2}=120\Omega$