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Question

Calculate 103×107 using algebraic identities.

A
10121
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B
11021
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C
10021
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D
12011
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Solution

The correct option is B 11021


We know that (x+a)(x+b)=x2+(a+b)x+ab

To split 103×107, we need a square that is easy to calculate.

Hence, x=100,a=3,b=7

103×107=(100+3)(100+7)
=1002+(3+7)(100)+(3)(7)
=10000+1000+21=11021


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