Calculate 103×107 using algebraic identities.
We know that (x+a)(x+b)=x2+(a+b)x+ab
To split 103×107, we need a square that is easy to calculate. Hence, x=100,a=3,b=7
∴103×107=(100+3)(100+7) =1002+(3+7)(100)+(3)(7) =10000+1000+21=11021
Find the value of (103)2 using algebraic identities.
Using the identities of algebraic expressions , find (i) 1002×1003 (ii) 97×103. [2 MARKS]