Calculate 2.5 x 10

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250

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0.25

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125

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Solution

The correct option is A
25

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Similar questions

0.05 M

K_{b}

K_{a}

H C N

K_{b} ({C N}^{-}) = 2.5 \times 10^{- 5}

K_{a}

H C N

K_{b} ({C N}^{-}) = 2.5 \times 10^{- 5}

If the value of the solubility product for AgBr is 4.0 x 10^-12at 25 °C, calculate the solubility of AgBr(s) in water.

2 m

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2 Ω

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