Calculate:
$(- 8 x^{3} - 16 x^{2} + 3 x + 6) : (x + 2)$

Open in App

Solution

$(x + 2) - 8 x^{3} + 16 x^{2} + 3 x + 6 (- 8 x^{2} + 3)$
$- 8 x^{3} - 16 x^{2}$
$+ +$
_______
$3 x + 6$
$3 x + 6$
$- -$
_
$0$
$∴ - 8 x^{3} - 16 x^{2} + 3 x + 6$ $= - 8 x^{2} + 3$
_______________
$x + 2$

Suggest Corrections

Similar questions

\sqrt{4 x^{4} + 8 x^{3} + 16 x^{2} + 12 x + 9}

x

16^{(x^{2} + 3 x - 1)} = 8^{(x^{2} + 3 x + 2)}

x_{1}, x_{2}, . . . . ., x_{6}

x^{6} + 2 x^{5} + 4 x^{4} + 8 x^{3} + 16 x^{2} + 32 x + 64 = 0

(\frac{3 x}{x + 5}) \div (\frac{6}{4 x + 20})

x \neq - 5

lim x \to - 2 / 3 \frac{6 x^{2} - 5 x - 6}{3 x^{2} - x - 2}

Join BYJU'S Learning Program