(i) 45÷[211×(−22−8)]
=45÷(211×228)
=45÷12
=45×2
=85
(ii) (35+59)÷(−2615)
⇒(27+2545)÷(−2615)
=−5245×1526
=−23
Solve:
(i) 2−35
(ii) 4+78
(iii) 35+27
(iv) 911−415
(v) 710+25+32
(vi) 223+312
(vii) 812−358
Find the sum:
(i) (ii) (iii)
(iv) (v) (vi)
(vii)