Question

Calculate and compete the energies of two radiations (1) with wavelength $800pm$ and (2) wavelength $400pm$.

Answer 1

We know $E=hv=hc/\lambda$

For comparing energy here these two radiation only differs in wavelength.Thus,

$\frac{E_1}{E_2}=\frac{{\lambda }_2}{{\lambda }_1}=\frac{400}{800}=\frac{1}{2}$