Calculate CFSE of the following complex:
$[C u (N H_{3})_{6}]^{2 +}$

0.4 Δ_{t}

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- 0.6 Δ_{0}

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2.4 Δ_{t}

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0.6 Δ_{0}

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Solution

The correct option is B $- 0.6 Δ_{0}$

$[C u (N H)_{3})_{6}]^{2 +}$

Here, $C u$ is in $d^{9}$ system and $N H_{3}$ is a low spin ligand, hence, electrons pairing will happen in $t_{2} g$ level.

$∴$ CFSE $= \frac{3}{5} \times 3 - \frac{2}{5} \times 6 = - 3 / 5 Δ_{o} = - 0.6 Δ_{o}$

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Similar questions

Q. Match Column I with Column II.

\begin{matrix} Column - I & Column - II (Complex ion) & (CFSE and hybridisation) a . {[C r (N H_{3})_{6}]}_{3}^{3 +} & (P) 0.0 Δ_{0}, s p^{3} d^{2} - hybridisation b . {[C u (N H_{3})_{6}]}_{3}^{2 +} & (Q) - 0.6 Δ_{0}, s p^{3} d^{2} - hybridisation c . {[F e (H_{2} O)_{6}]}_{2}^{3 +} & (R) - 1.2 Δ_{0}, d^{2} s p^{3} - hybridisation d . {[I r F_{6}]}_{6}^{3 -} & (S) Diamagnetic (T) Paramagnetic \end{matrix}

Q. Calculate crystal field stabilization energy for the complex

[C u (N H_{3})_{6}]^{2 +}

Q. Calculate CFSE of the following complexes :

[F e (C N)_{6}]^{4 -}

Calculate CFSE of the following complexes :

[C o F_{6}]^{3 -}

Give the electronic configuration of the following complexes on the basis of crystal field splitting theory. $[C o F_{6}]^{3 -}, [F e (C N)_{6}]^{4 -}$ and $[C u (N H_{3})_{6}]^{2 +} .$

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Calculate CFSE of the following complex:[Cu(NH3)6]2+

The correct option is B −0.6Δ0[Cu(NH)3)6]2+Here, Cu is in d9 system and NH3 is a low spin ligand, hence, electrons pairing will happen in t2g level.∴CFSE =35×3−25×6=−3/5Δo=−0.6Δo

Calculate CFSE of the following complex:
$[C u (N H_{3})_{6}]^{2 +}$

The correct option is B $- 0.6 Δ_{0}$

$[C u (N H)_{3})_{6}]^{2 +}$

Here, $C u$ is in $d^{9}$ system and $N H_{3}$ is a low spin ligand, hence, electrons pairing will happen in $t_{2} g$ level.

$∴$ CFSE $= \frac{3}{5} \times 3 - \frac{2}{5} \times 6 = - 3 / 5 Δ_{o} = - 0.6 Δ_{o}$