Calculate coefficients $a, b, c$ and $d$ in the following equation:
$a M g_{3} N_{2} + b H_{2} O \to M g (O H)_{2} + d N H_{3}$

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Solution

To balance the equation

$a$ $M g_{3} N_{2} + b$ $H_{2} O \to M g (O H)_{2} + d N H_{3}$

Go by trial and error method first balancing metals and lastly oxygen

$M g_{3} N_{2} + 6$ $H_{2} O \to 3 M g (O H)_{2} + 2 N H_{3}$

Hence $a = 1, b = 6, c = 3, d = 2$

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