Question

Calculate currect ${}^{\prime }{I}^{\prime }$ in $10\Omega$ resistance.

• A. $1\text{A}$
• B. $2\text{A}$
• C. $\frac{2}{5}\text{A}$
• D. $\frac{1}{56}\text{A}$

Answer 1

The correct option is D $\frac{1}{56}\text{A}$

Applying $KVL$ in upper loop,
$-3+2I_1+10I=0$
$\Rightarrow I_1=\frac{3-10I}{2}......\left(i\right)$
Similarly, in lower loop,
$-10I-5+3(I_1-I)=0$
$\Rightarrow -13I+3I_1-5=0$
$\Rightarrow -13I+3\left(\frac{3-10I}{2}\right)-5=0$
$\Rightarrow -26I+9-30I-10=0$
$\Rightarrow I=-\frac{1}{56}\text{A}$
(-ve sign indicates the current direction is opposite to what we assumed)
$\therefore |I|=\frac{1}{56}\text{A}$