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Question

Calculate de-Broglie wavelength of an electron having kinetic energy of 1 GeV. Given mass of electron m=9.1×1031 kg, h=6.6×1034 Js and e=1.6×1019 C

A
78×1014 m
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B
7.8×1014 m
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C
3.8×1014 m
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D
38×1014 m
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Solution

The correct option is C 3.8×1014 m
Given,

K.E=1 GeV=109 eV=1.6×1010 J

The de-Broglie wavelength is given by,

λ=h2mKE=6.6×10342×9.1×1031×1.6×1010

=6.6×10341.70×1020=3.8×1014 m

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (C) is the correct answer.

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