wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Calculate de-Broglie wavelength of an electron having kinetic energy of 1 GeV. Given mass of electron m=9.1×1031 kg, h=6.6×1034 Js and e=1.6×1019 C

A
7.8×1014 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
38×1014 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.8×1014 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
78×1014 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 3.8×1014 m
Given,

K.E=1 GeV=109 eV=1.6×1010 J

The de-Broglie wavelength is given by,

λ=h2mKE=6.6×10342×9.1×1031×1.6×1010

=6.6×10341.70×1020=3.8×1014 m

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (C) is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
de Broglie's Hypothesis
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon