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Question

Calculate ΔfG for (NH4Cl,(s)) at 300 K.
Given: ΔfH(NH4Cl,s)=314.5kJ/mol:ΔrCp=0
SN2(g)=192JK1mol1; SH2(g)=130.5JK1mol1SCl2(g)=233JK1mol1;SNH4Cl(s)=99.5JK1mol1
All given data at 300 K.

A
193.56 kJ mol1
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B
426.7 kJ mol1
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C
202.3 kJ mol1
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D
None of these
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Solution

The correct option is C 202.3 kJ mol1
12N2(g) + 2H2(g) + 12Cl2(g) NH4Cl(s)

ΔfS(NH4Cl,s) at 300K=SNH4Cl(s)[12SN2+2SH2+12SCl2]=374 J K1 mol1ΔrCp=0Δff300=ΔfS300=374 J K1mol1ΔfH300=314.5 kJ mol1ΔfG300=ΔfH300ΔS=314.5300(374)1000=202.3 kJ mol1

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