Calculate ΔfG∘ for (NH4Cl,(s)) at 300K.
Given: ΔfH∘(NH4Cl,s)=−314.5kJ/mol:ΔrCp=0 S∘N2(g)=192JK−1mol−1;S∘H2(g)=130.5JK−1mol−1S∘Cl2(g)=233JK−1mol−1;S∘NH4Cl(s)=99.5JK−1mol−1
All given data at 300K.
A
−193.56kJmol−1
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B
−426.7kJmol−1
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C
−202.3kJmol−1
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D
None of these
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Solution
The correct option is C−202.3kJmol−1 12N2(g)+2H2(g)+12Cl2(g)→NH4Cl(s)