Question

Calculate $\Delta$ H and $\Delta$G values in Joules.

• A. $0,0$
• B. $5227,0$
• C. $0,-5227$
• D. $-5227,0$

Answer 1

The correct option is C $0,-5227$

For an isothermal reversible process,

$W=-2.303nRT\log \frac{P_1}{P_2}$

$W=-2.303\times 1\times 8.314\times 273\times \log \frac{1.0}{0.1}$

$W=-5227.2J$

Again,

$q=\Delta E-W$

At constant temperature $\Delta T=0,\Delta E=0$
$q=-W=+5227.2J$

$\Delta H=\Delta E+\Delta \left(PV\right)$

When T is constant $P_1{V}_1=P_2{V}_2;PV=$ constant

$\Delta H=\Delta E=0$

$\Delta S=\frac{q}{T}=\frac{5227.2}{273}$

$\Delta G=\Delta H-T\Delta S$

$=0-273\times \frac{5227.2}{273}=-5227.2J$