Calculate - H for Cgraphite- Cdiamond from the following data-i Cgraphite-O2- CO2g- H-94 Kcalii Cdiamond-O2- CO2g- H-68 Kcal

The correct option is B 26 Kcali) C (graphite) + #160;O_2→ CO_2(g) #160;Δ H= 94 Kcalii) C (diamond) + #160;O_2→ CO_2(g) #160;Δ H= 68 Kca ...

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Calculate Δ...

Question

Calculate $Δ H$ for $C_{(g r a p h i t e)} \to C_{d i a m o n d}$ from the following data:
i) $C (g r a p h i t e) + O_{2} \to C O_{2} (g), Δ H = - 94 K c a l$
ii) $C (d i a m o n d) + O_{2} \to C O_{2} (g), Δ H = - 68 K c a l$

-13 Kcal

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-26 Kcal

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162 Kcal

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-81 Kcal

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Δ H

C (d i a m o n d) + O_{2} \to C O_{2} (g); Δ H = - 94.5 K c a l

C (g r a p h i t e) + O_{2} \to C O_{2} (g); Δ H = - 94 K c a l

C_{d i a m o n d} \to C_{(g r a p h i t e)}

(i n k c a l)

C_{(d i o m o n d)} + O_{2} (g) \to C O_{2} (g) . . . (i) (Δ H = - 94.5 k c a l) C_{(g r a p h i t e)} + O_{2} (g) \to C O_{2} (g) . . . (i i) (Δ H = - 94.0 k c a l)

C_{D i a m o n d} + O_{2} \to C O_{2} (g); Δ H = - 94.3 k c a l

C_{G r a p h i t e} + O_{2} \to C O_{2} (g); Δ H = - 97.6 k c a l

C_{d i a m o n d} \to C_{g r a p h i t e}

Δ H

C (g r a p h i t e) \to C (d i a m o n d)

C (g r a p h i t e) + O_{2} (g) ⟶ C O_{2} (g); Δ H^{o} = - 393.5 k J

C (g r a p h i t e) + O_{2} (g) ⟶ C O_{2} (g); Δ H^{o} = - 395.4 k J

C (s) + O_{2} (g) \to C O_{2} (g); Δ H = - 94.3

C O (g) + 1 / 2 O_{2} (g) \to C O_{2} (g); Δ H = - 67.4

O_{2} (g) \to 2 O (g); Δ H = 117.4

C O (g) \to C (g) + O (g); Δ H = 230.6

Δ H

C (s)

\to

C (g)

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