Calculate -H o of the reaction 2NaBr - Cl2 - 2NaCl - Br2- if there is known the -H o of substances formation- -H o NaBr- -361 KJ-mol -H o NaCl- -411 KJ-mol

2NaBr+Cl_2⟶ 2NaCl+Br_2; _rH^∘ _rH^∘ =∑ H^∘(products) ∑ H^∘(reactants) =2 H^∘(NaBr)+ H^∘(Cl_2) 2 H^∘ #160; (NaCl) H^∘ #160; (Br) =2 ...

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Bond Order and Enthalpy

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Question

Calculate $Δ H^{o}$ of the reaction $2 N a B r + C l_{2} = 2 N a C l + {B r}_{2}$ , if there is known the $Δ H^{o}$ of substances formation:
$Δ H^{o} (N a B r) = - 361 K J / m o l$
$Δ H^{o} (N a C l) = - 411 K J / m o l$

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- X

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