Calculate ΔrG for the reaction at 27∘C H2(g)+2Ag+(aq)⇌2Ag(s)+2H+(aq)
Given : PH2=0.5bar;[Ag+]=10−5M [H+]=10−3M;ΔrG∘[Ag+(aq)]=77.1kJmol−1 (Given,ln(2×104)=9.90)
A
−154.2kJmol−1
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B
−178.9kJmol−1
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C
−129.5kJmol−1
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D
None of these
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Solution
The correct option is C−129.5kJmol−1 ΔrG∘=0−77.1×2=−154.2kJmol−1Q=[H+]2PH2[Ag+]2=10−60.5×(10−10)=2×104ΔG=ΔrG∘+RTlnQΔrG=−154.2+8.314×10−3×300ln(2×104)=−129.5kJmol−1