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Characteristics of Equilibrium Constant

Calculate Δr ...

Question

Calculate $Δ_{r} G$ for the reaction at $27^{\circ} C$
$H_{2} (g) + 2 A g^{+} (a q) ⇌ 2 A g (s) + 2 H^{+} (a q)$
Given : $P_{H_{2}} = 0.5 b a r; [A g^{+}] = 10^{- 5} M$
$[H^{+}] = 10^{- 3} M; Δ_{r} G^{\circ} [A g^{+} (a q)] = 77.1 k J m o l^{- 1}$
$(G i v e n, l n (2 \times 10^{4}) = 9.90)$

- 154.2 k J m o l^{- 1}

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- 178.9 k J m o l^{- 1}

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- 129.5 k J m o l^{- 1}

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None of these

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Solution

The correct option is C $- 129.5 k J m o l^{- 1}$
$Δ_{r} G^{\circ} = 0 - 77.1 \times 2 = - 154.2 k J m o l^{- 1} Q = \frac{[H^{+}]^{2}}{P_{H_{2}} [A g^{+}]^{2}} = \frac{10^{- 6}}{0.5 \times (10^{- 10})} = 2 \times 10^{4} Δ G = Δ_{r} G^{\circ} + R T l n Q Δ_{r} G = - 154.2 + 8.314 \times 10^{- 3} \times 300 l n (2 \times 10^{4}) = - 129.5 k J m o l^{- 1}$

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Similar questions

Δ_{r} G

27^{\circ} C

H_{2} (g) + 2 A g^{+} (a q) ⇌ 2 A g (s) + 2 H^{+} (a q)

P_{H_{2}} = 0.5 b a r; [A g^{+}] = 10^{- 5} M

[H^{+}] = 10^{- 3} M; Δ_{r} G^{\circ} [A g^{+} (a q)] = 77.1 k J m o l^{- 1}

(G i v e n, l n (2 \times 10^{4}) = 9.90)

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H_{2} (g) + 2 {A g}^{+} (a q) ⇌ 2 A g (s) + 2 H^{+} (a q)

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0.5 bar; [A g^{+}] = 10^{- 5} M; log 2 =0.3 log 2= 0.7

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