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Question

Calculate ΔU and ΔH in calories if 1 mole of a monoatomic ideal gas is heated at constant pressure of 1 atm from 25oC to 50oC.

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Solution

For monoatomic ideal gas, Cv=32R
Cp=ΔHΔT

ΔH=CpΔT mol1 ( or nCpΔT for n moles )
=52×1.987×25=124.2 cal
Work done,
w=PΔV=P(V2V1)
=(PV2PV1)=(nRT2nRT1)
=mR(T2T1)
=1×1.987(323298) cal
=49.7 cal
ΔE=q+w
=124.249.7 cal=74.5 cal.

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